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Extending default scope to typeclass parameters
For reference, see this question about the implementation of the default scope typeclass:
Default scope: thinking outside the box
What I'm trying to do is to create a typeclass which allows the type parameter T (from an applicative functor f) to be part of the default scope of any function-like object. To illustrate, suppose I have:
class Monad f => Functor f where
fmap :: f a -> (a -> b) -> f b
class Functor f => Default f where
default :: a -> f a
Then I can use fmap on a Functor instance like this:
> default (\x -> x + 1) -1
Just 2
which is the value I want - a function that subtracts 1 from something and returns the result. However, I want default to also work like this:
> -- I want this function to be part of the default scope
> const $ \x -> \y -> y + 1
5
I don't mind if this is wrong syntax. The reason I have it as a member function is so that it can do things like const $ \x -> \y -> x + 1 -- which I think is clear from the comment: the const keyword becomes part of the function. I also know this doesn't work because of the default constraints.
I can't seem to construct such a type class. Here is my attempt to create one:
class Functor f => Default f where
defDefault :: a -> f a
defDefault (x :: a) = \y -> y + 1 0b46394aab
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